[求助]此程序怎么判断如果输入的除数为0？

枫飘雪

如题
程序如下：
#!/bin/bash

echo "Caculator:"
while true
do
echo -n "a)+   b)-   c)*   d)/  x)=exit     "
echo -n "input:"

read op
case $op in
a) op="+" ;;
b) op="-" ;;
c) op="*" ;;
d) op="/" ;;
x) exit ;;
*) echo "wrong ,input again..."
continue ;;
esac
echo "input two numbers:"
read n1 n2

echo -n "$n1""$op""$n2"
RESULT=$[$n1$op$n2]
echo "="$RESULT
echo -n "continue (y/n)? "
read answer
case $answer in
n) break;;
y) continue;;
*) echo "wrong input!! error!!!"
break;;
esac
done
echo "bye"

小弟刚刚学习
此程序也是改来改去的。

sprite

#!/bin/bash

echo "Caculator:"
while true
do
echo -n "a)+ b)- c)* d)/ x)=exit "
echo -n "input:"

read op
case $op in
a) op="+" ;;
b) op="-" ;;
c) op="*" ;;
d) op="/" ;;
x) exit ;;
*) echo "wrong ,input again..."
continue ;;
esac
echo "input two numbers:"
read n1 n2

echo -n "$n1""$op""$n2"
if test $op="/" && test $n2 -eq 0
then
echo divide by 0
else
RESULT=$[$n1$op$n2]
echo "="$RESULT
fi

echo -n "continue (y/n)? "
read answer
case $answer in
n) break;;
y) continue;;
*) echo "wrong input!! error!!!"
break;;
esac
done
echo "bye"

枫飘雪

如果这样的话，算加法的时候第2个数也不能为0了。要其他算法也正常的

sprite

sorry没有仔细调试，写得不好。
把判断部分改成这样：

if [ "$op" = "/" ] && [ "$n2" = "0" ]