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- #!/bin/sh
- for ((d1 in `awk -F= '{print $1}' log.txt`; d2 in `awk -F= '{print $2}' log.txt`; d3 in `awk -F= '{print $3}' log.txt`))
- do
- echo $d1 "name is "$d2 "on "$d3
- done
复制代码
[root@Yuri studen]# cat log.txt
1=default=2005-7-11=1nb.bak
2=userbackup=2005-7-11=2nb.bak
3=333=333=3nb.bak
4=444=444=4nb.bak
5=555=555=5nb.bak
[root@Yuri studen]#
我想要的结果是
1 name is default on 2005-7-11
2 name is userbackup on 2005711
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