字符串比较大小

wdl36

set a = 50%
set b = 60%
能比较a ,b 的大小么？

或者可以用其他方法比较2个百分数之间的大小么/

KornLee

bash/ksh:

1. 
   
2. [[ ${a%%%* -gt ${b%%%*} ]]&&echo $a is big||echo $b is big

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楼主用的是csh吧~,,呵呵,不熟悉
用awk比较通用

1. 
   
2. [lee@linux ~]$ set a=60%
   
3. [lee@linux ~]$ set b=50%
   
4. [lee@linux ~]$ awk -v a=$a -v b=$b 'BEGIN{if(a>b)print "a is big";else print "b is big"}'
   

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wdl36

新手，只用过CSH，还不知道其他的强大之处。

我执行上面的语句，结果：
awk -v a=$a -v b=$b 'BEGIN{if(a>b)print "a is big";else print "b is big"}'
a: Undefined variable

KornLee

/home/lee#csh
[lee@linux ~]$ set a=60%
[lee@linux ~]$ set b=50%
[lee@linux ~]$ awk -v a=$a -v b=$b 'BEGIN{if(a>b)print "a is big";else print "b is big"}'
a is big
[lee@linux ~]$ set a=30%
[lee@linux ~]$ set b=50%
[lee@linux ~]$ awk -v a=$a -v b=$b 'BEGIN{if(a>b)print "a is big";else print "b is big"}'
b is big
[lee@linux ~]$ awk --version
GNU Awk 3.1.1
Copyright (C) 1989, 1991-2002 Free Software Foundation.

wdl36

多谢，版本的差异..........